Nonstop flight route between Jorhat, India and Lake Ozark, Missouri, United States:
Departure Airport:
Arrival Airport:
Distance from JRH to AIZ:
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- About this route
- JRH Airport Information
- AIZ Airport Information
- Facts about JRH
- Facts about AIZ
- Map of Nearest Airports to JRH
- List of Nearest Airports to JRH
- Map of Furthest Airports from JRH
- List of Furthest Airports from JRH
- Map of Nearest Airports to AIZ
- List of Nearest Airports to AIZ
- Map of Furthest Airports from AIZ
- List of Furthest Airports from AIZ
About this route:
A direct, nonstop flight between Jorhat Airport (JRH), Jorhat, India and Lee C. Fine Memorial Airport (AIZ), Lake Ozark, Missouri, United States would travel a Great Circle distance of 7,937 miles (or 12,773 kilometers).
A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the large distance between Jorhat Airport and Lee C. Fine Memorial Airport, the route shown on this map most likely appears curved because of this reason.
Try it at home! Get a globe and tightly lay a string between Jorhat Airport and Lee C. Fine Memorial Airport. You'll see that it will travel the same route of the red line on this map!
Departure Airport Information:
IATA / ICAO Codes: | JRH / VEJT |
Airport Names: |
|
Location: | Jorhat, India |
GPS Coordinates: | 26°43'54"N by 94°10'32"E |
Area Served: | Jorhat, Golaghat |
Operator/Owner: | Indian Air Force Airports Authority of India |
Airport Type: | Military/Public |
Elevation: | 311 feet (95 meters) |
# of Runways: | 1 |
View all routes: | Routes from JRH |
More Information: | JRH Maps & Info |
Arrival Airport Information:
IATA / ICAO Codes: | AIZ / KAIZ |
Airport Name: | Lee C. Fine Memorial Airport |
Location: | Lake Ozark, Missouri, United States |
GPS Coordinates: | 38°5'45"N by 92°32'58"W |
Operator/Owner: | City of Osage Beach |
Airport Type: | Public |
Elevation: | 869 feet (265 meters) |
# of Runways: | 1 |
View all routes: | Routes from AIZ |
More Information: | AIZ Maps & Info |
Facts about Jorhat Airport (JRH):
- Because of Jorhat Airport's relatively low elevation of 311 feet, planes can take off or land at Jorhat Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
- The closest airport to Jorhat Airport (JRH) is Lilabari Airport (IXI), which is located 39 miles (63 kilometers) N of JRH.
- The furthest airport from Jorhat Airport (JRH) is La Florida Airport (LSC), which is located 11,521 miles (18,542 kilometers) away in La Serena, Chile.
- Jorhat Airport (JRH) currently has only 1 runway.
- In addition to being known as "Jorhat Airport", other names for JRH include "Rowriah Airport", "যোৰহাট বিমানবন্দৰ" and "जोरहाट हवाई अड्डे".
Facts about Lee C. Fine Memorial Airport (AIZ):
- Lee C. Fine Memorial Airport (AIZ) currently has only 1 runway.
- The furthest airport from Lee C. Fine Memorial Airport (AIZ) is Margaret River Airport (MGV), which is located 10,871 miles (17,495 kilometers) away in Margaret River, Western Australia, Australia.
- Because of Lee C. Fine Memorial Airport's relatively low elevation of 869 feet, planes can take off or land at Lee C. Fine Memorial Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
- The closest airport to Lee C. Fine Memorial Airport (AIZ) is Waynesville-St. Robert Regional Airport (TBN), which is located 33 miles (53 kilometers) SE of AIZ.