Nonstop flight route between Pagadian City, Zamboanga del Sur, Philippines and Jacksonville, Texas, United States:
Departure Airport:
Arrival Airport:
Distance from PAG to JKV:
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- About this route
- PAG Airport Information
- JKV Airport Information
- Facts about PAG
- Facts about JKV
- Map of Nearest Airports to PAG
- List of Nearest Airports to PAG
- Map of Furthest Airports from PAG
- List of Furthest Airports from PAG
- Map of Nearest Airports to JKV
- List of Nearest Airports to JKV
- Map of Furthest Airports from JKV
- List of Furthest Airports from JKV
About this route:
A direct, nonstop flight between Pagadian Airport (PAG), Pagadian City, Zamboanga del Sur, Philippines and Cherokee County Airport (JKV), Jacksonville, Texas, United States would travel a Great Circle distance of 8,692 miles (or 13,988 kilometers).
A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the large distance between Pagadian Airport and Cherokee County Airport, the route shown on this map most likely appears curved because of this reason.
Try it at home! Get a globe and tightly lay a string between Pagadian Airport and Cherokee County Airport. You'll see that it will travel the same route of the red line on this map!
Departure Airport Information:
IATA / ICAO Codes: | PAG / RPMP |
Airport Names: |
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Location: | Pagadian City, Zamboanga del Sur, Philippines |
GPS Coordinates: | 7°49'37"N by 123°27'29"E |
Area Served: | Pagadian City |
Operator/Owner: | Civil Aviation Authority of the Philippines |
Airport Type: | Public |
Elevation: | 5 feet (2 meters) |
# of Runways: | 1 |
View all routes: | Routes from PAG |
More Information: | PAG Maps & Info |
Arrival Airport Information:
IATA / ICAO Codes: | JKV / KJSO |
Airport Names: |
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Location: | Jacksonville, Texas, United States |
GPS Coordinates: | 31°52'9"N by 95°13'3"W |
Area Served: | Jacksonville, Texas |
Operator/Owner: | Cherokee County |
Airport Type: | Public |
Elevation: | 677 feet (206 meters) |
# of Runways: | 1 |
View all routes: | Routes from JKV |
More Information: | JKV Maps & Info |
Facts about Pagadian Airport (PAG):
- The closest airport to Pagadian Airport (PAG) is Labo Airport (OZC), which is located 36 miles (57 kilometers) NE of PAG.
- In addition to being known as "Pagadian Airport", another name for PAG is "Paliparan ng PagadianTugpahanan sa Pagadian".
- Pagadian Airport (PAG) currently has only 1 runway.
- On October 9, 2009, Former President Gloria Macapagal-Arroyo inaugurated the renovated airport.
- Because of Pagadian Airport's relatively low elevation of 5 feet, planes can take off or land at Pagadian Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
- The furthest airport from Pagadian Airport (PAG) is Piloto Osvaldo Marques Dias Airport (AFL), which is nearly antipodal to Pagadian Airport (meaning Pagadian Airport is almost on the exact opposite side of the Earth from Piloto Osvaldo Marques Dias Airport), and is located 12,293 miles (19,783 kilometers) away in Alta Floresta, Brazil.
Facts about Cherokee County Airport (JKV):
- In addition to being known as "Cherokee County Airport", another name for JKV is "JSO".
- Cherokee County Airport (JKV) currently has only 1 runway.
- Cherokee County Airport covers an area of 224 acres at an elevation of 677 feet above mean sea level.
- The closest airport to Cherokee County Airport (JKV) is Tyler Pounds Regional Airport (TYR), which is located 35 miles (57 kilometers) NNW of JKV.
- The furthest airport from Cherokee County Airport (JKV) is Cocos (Keeling) Island Airport (CCK), which is located 10,876 miles (17,503 kilometers) away in Cocos Islands, Australia.
- Because of Cherokee County Airport's relatively low elevation of 677 feet, planes can take off or land at Cherokee County Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.