Nonstop flight route between Cleveland, Ohio, United States and Excursion Inlet, Alaska, United States:

About this route:

A direct, nonstop flight between Cleveland Hopkins International Airport (CLE), Cleveland, Ohio, United States and Excursion Inlet Seaplane Base (EXI), Excursion Inlet, Alaska, United States would travel a Great Circle distance of 2,570 miles (or 4,136 kilometers).

A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the large distance between Cleveland Hopkins International Airport and Excursion Inlet Seaplane Base, the route shown on this map most likely appears curved because of this reason.

Try it at home! Get a globe and tightly lay a string between Cleveland Hopkins International Airport and Excursion Inlet Seaplane Base. You'll see that it will travel the same route of the red line on this map!

Departure Airport Information:

Arrival Airport Information:

Facts about Cleveland Hopkins International Airport (CLE):

• On May 2, 2010, the Boards of Directors at Continental and United Airlines approved a stock-swap merger deal.
• Cleveland Hopkins International Airport (CLE) has 3 runways.
• ^1 All Air Canada arrivals are completed through the United States border preclearance.
• The closest airport to Cleveland Hopkins International Airport (CLE) is Cleveland Burke Lakefront Airport (BKL), which is located only 11 miles (18 kilometers) NE of CLE.
• Because of Cleveland Hopkins International Airport's relatively low elevation of 791 feet, planes can take off or land at Cleveland Hopkins International Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
• Cleveland Hopkins International Airport is a public airport located nine miles southwest of the central business district of Cleveland, a city in Cuyahoga County, Ohio, United States.
• The furthest airport from Cleveland Hopkins International Airport (CLE) is Margaret River Airport (MGV), which is located 11,378 miles (18,311 kilometers) away in Margaret River, Western Australia, Australia.
• For weather-related issues, United would sometimes divert EWR-bound international 767s and 777s into CLE.

Facts about Excursion Inlet Seaplane Base (EXI):

• Excursion Inlet Seaplane Base has one seaplane landing area designated NW/SE with a water surface measuring 1,000 by 1,000 feet.
• The closest airport to Excursion Inlet Seaplane Base (EXI) is Gustavus Airport (GST), which is located only 9 miles (15 kilometers) W of EXI.
• Because of Excursion Inlet Seaplane Base's relatively low elevation of 0 feet, planes can take off or land at Excursion Inlet Seaplane Base at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
• This airport is included in the National Plan of Integrated Airport Systems for 2011–2015, which categorized it as a general aviation airport.
• Excursion Inlet Seaplane Base (EXI) currently has only 1 runway.
• The furthest airport from Excursion Inlet Seaplane Base (EXI) is Port Elizabeth International Airport (PLZ), which is located 10,536 miles (16,956 kilometers) away in Port Elizabeth, South Africa.