Nonstop flight route between Excursion Inlet, Alaska, United States and Chesapeake, Ohio / Huntington, West Virginia, United States:
Departure Airport:

Arrival Airport:

Distance from EXI to HTW:
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- About this route
- EXI Airport Information
- HTW Airport Information
- Facts about EXI
- Facts about HTW
- Map of Nearest Airports to EXI
- List of Nearest Airports to EXI
- Map of Furthest Airports from EXI
- List of Furthest Airports from EXI
- Map of Nearest Airports to HTW
- List of Nearest Airports to HTW
- Map of Furthest Airports from HTW
- List of Furthest Airports from HTW
About this route:
A direct, nonstop flight between Excursion Inlet Seaplane Base (EXI), Excursion Inlet, Alaska, United States and Lawrence County Airpark (HTW), Chesapeake, Ohio / Huntington, West Virginia, United States would travel a Great Circle distance of 2,698 miles (or 4,342 kilometers).
A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the large distance between Excursion Inlet Seaplane Base and Lawrence County Airpark, the route shown on this map most likely appears curved because of this reason.
Try it at home! Get a globe and tightly lay a string between Excursion Inlet Seaplane Base and Lawrence County Airpark. You'll see that it will travel the same route of the red line on this map!
Departure Airport Information:
IATA / ICAO Codes: | EXI / |
Airport Name: | Excursion Inlet Seaplane Base |
Location: | Excursion Inlet, Alaska, United States |
GPS Coordinates: | 58°25'14"N by 135°26'57"W |
Area Served: | Excursion Inlet, Alaska |
Operator/Owner: | State of Alaska DOT&PF - Southeast Region |
Airport Type: | Public |
Elevation: | 0 feet (0 meters) |
# of Runways: | 1 |
View all routes: | Routes from EXI |
More Information: | EXI Maps & Info |
Arrival Airport Information:
IATA / ICAO Codes: | HTW / KHTW |
Airport Name: | Lawrence County Airpark |
Location: | Chesapeake, Ohio / Huntington, West Virginia, United States |
GPS Coordinates: | 38°25'9"N by 82°29'39"W |
Area Served: | Chesapeake, Ohio / Huntington, West Virginia |
Operator/Owner: | Lawrence County Board of Commissioners |
Airport Type: | Public |
Elevation: | 568 feet (173 meters) |
# of Runways: | 1 |
View all routes: | Routes from HTW |
More Information: | HTW Maps & Info |
Facts about Excursion Inlet Seaplane Base (EXI):
- The furthest airport from Excursion Inlet Seaplane Base (EXI) is Port Elizabeth International Airport (PLZ), which is located 10,536 miles (16,956 kilometers) away in Port Elizabeth, South Africa.
- Because of Excursion Inlet Seaplane Base's relatively low elevation of 0 feet, planes can take off or land at Excursion Inlet Seaplane Base at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
- The closest airport to Excursion Inlet Seaplane Base (EXI) is Gustavus Airport (GST), which is located only 9 miles (15 kilometers) W of EXI.
- Excursion Inlet Seaplane Base (EXI) currently has only 1 runway.
Facts about Lawrence County Airpark (HTW):
- The 1930s were marked by repeated attempts to establish passenger and mail service to the H-I-C Airport.
- The closest airport to Lawrence County Airpark (HTW) is Tri-State Airport (HTS), which is located only 5 miles (8 kilometers) SW of HTW.
- The furthest airport from Lawrence County Airpark (HTW) is Margaret River Airport (MGV), which is located 11,410 miles (18,362 kilometers) away in Margaret River, Western Australia, Australia.
- Lawrence County Airpark (HTW) currently has only 1 runway.
- Because of Lawrence County Airpark's relatively low elevation of 568 feet, planes can take off or land at Lawrence County Airpark at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
- Lawrence County Airpark covers an area of 86 acres at an elevation of 568 feet above mean sea level.
- Lawrence County Airpark is a public use airport located two nautical miles west of the central business district of Chesapeake, a village in Lawrence County, Ohio, United States.