Nonstop flight route between Provideniya, Chukotka, Russia and Amook Bay, Alaska, United States:

About this route:

A direct, nonstop flight between Provideniya Bay Airport (PVS), Provideniya, Chukotka, Russia and Amook Bay Seaplane Base (AOS), Amook Bay, Alaska, United States would travel a Great Circle distance of 803 miles (or 1,292 kilometers).

A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the relatively short distance between Provideniya Bay Airport and Amook Bay Seaplane Base, the route shown on this map most likely still appears to be a straight line.

Departure Airport Information:

Arrival Airport Information:

Facts about Provideniya Bay Airport (PVS):

• The closest airport to Provideniya Bay Airport (PVS) is Gambell Airport (GAM), which is located 62 miles (100 kilometers) SE of PVS.
• Provideniya Bay Airport (PVS) currently has only 1 runway.
• The furthest airport from Provideniya Bay Airport (PVS) is Teniente Rodolfo Marsh Airport (TNM), which is located 10,481 miles (16,867 kilometers) away in Villa Las Estrellas, Antarctica.
• Because of Provideniya Bay Airport's relatively low elevation of 72 feet, planes can take off or land at Provideniya Bay Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
• In addition to being known as "Provideniya Bay Airport", another name for PVS is "Аэропорт «Бухта Провидения»".

Facts about Amook Bay Seaplane Base (AOS):

• Although classified by the FAA as "private use", Amook Bay has scheduled passenger service to Kodiak, Alaska, which is subsidized by the United States Department of Transportation via the Essential Air Service program.
• The furthest airport from Amook Bay Seaplane Base (AOS) is Port Elizabeth International Airport (PLZ), which is located 10,814 miles (17,403 kilometers) away in Port Elizabeth, South Africa.
• Because of Amook Bay Seaplane Base's relatively low elevation of 0 feet, planes can take off or land at Amook Bay Seaplane Base at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
• In addition to being known as "Amook Bay Seaplane Base", another name for AOS is "AK81".
• Amook Bay Seaplane Base (AOS) currently has only 1 runway.
• Amook Bay Seaplane Base is a privately owned seaplane base located in Amook Bay, a community in the Kodiak Island Borough of the U.S.
• The closest airport to Amook Bay Seaplane Base (AOS) is Zachar Bay Seaplane Base (KZB), which is located only 6 miles (10 kilometers) NNE of AOS.