Nonstop flight route between Tiniteqilaaq, Greenland and Amook Bay, Alaska, United States:

About this route:

A direct, nonstop flight between Tiniteqilaaq Heliport (TQI), Tiniteqilaaq, Greenland and Amook Bay Seaplane Base (AOS), Amook Bay, Alaska, United States would travel a Great Circle distance of 3,296 miles (or 5,304 kilometers).

A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the large distance between Tiniteqilaaq Heliport and Amook Bay Seaplane Base, the route shown on this map most likely appears curved because of this reason.

Try it at home! Get a globe and tightly lay a string between Tiniteqilaaq Heliport and Amook Bay Seaplane Base. You'll see that it will travel the same route of the red line on this map!

Departure Airport Information:

Arrival Airport Information:

Facts about Tiniteqilaaq Heliport (TQI):

• The closest airport to Tiniteqilaaq Heliport (TQI) is Tasiilaq Heliport (AGM), which is located only 19 miles (31 kilometers) SSE of TQI.
• The furthest airport from Tiniteqilaaq Heliport (TQI) is Hobart International Airport (HBA), which is located 10,832 miles (17,432 kilometers) away in Hobart, Tasmania, Australia.
• Because of Tiniteqilaaq Heliport's relatively low elevation of 15 feet, planes can take off or land at Tiniteqilaaq Heliport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.

Facts about Amook Bay Seaplane Base (AOS):

• Because of Amook Bay Seaplane Base's relatively low elevation of 0 feet, planes can take off or land at Amook Bay Seaplane Base at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
• Amook Bay Seaplane Base (AOS) currently has only 1 runway.
• Amook Bay Seaplane Base is a privately owned seaplane base located in Amook Bay, a community in the Kodiak Island Borough of the U.S.
• The furthest airport from Amook Bay Seaplane Base (AOS) is Port Elizabeth International Airport (PLZ), which is located 10,814 miles (17,403 kilometers) away in Port Elizabeth, South Africa.
• Amook Bay Seaplane Base has one seaplane landing area designated N/S with a water surface measuring 8,000 by 700 feet.
• The closest airport to Amook Bay Seaplane Base (AOS) is Zachar Bay Seaplane Base (KZB), which is located only 6 miles (10 kilometers) NNE of AOS.
• In addition to being known as "Amook Bay Seaplane Base", another name for AOS is "AK81".