Nonstop flight route between Clinton, Iowa, United States and Amook Bay, Alaska, United States:

About this route:

A direct, nonstop flight between Clinton Municipal Airport (CWI), Clinton, Iowa, United States and Amook Bay Seaplane Base (AOS), Amook Bay, Alaska, United States would travel a Great Circle distance of 2,914 miles (or 4,689 kilometers).

A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the large distance between Clinton Municipal Airport and Amook Bay Seaplane Base, the route shown on this map most likely appears curved because of this reason.

Try it at home! Get a globe and tightly lay a string between Clinton Municipal Airport and Amook Bay Seaplane Base. You'll see that it will travel the same route of the red line on this map!

Departure Airport Information:

Arrival Airport Information:

Facts about Clinton Municipal Airport (CWI):

• Clinton Municipal Airport (CWI) has 2 runways.
• The closest airport to Clinton Municipal Airport (CWI) is Davenport Municipal Airport (DVN), which is located 20 miles (33 kilometers) SW of CWI.
• The furthest airport from Clinton Municipal Airport (CWI) is Margaret River Airport (MGV), which is located 10,953 miles (17,628 kilometers) away in Margaret River, Western Australia, Australia.
• Because of Clinton Municipal Airport's relatively low elevation of 708 feet, planes can take off or land at Clinton Municipal Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.

Facts about Amook Bay Seaplane Base (AOS):

• The furthest airport from Amook Bay Seaplane Base (AOS) is Port Elizabeth International Airport (PLZ), which is located 10,814 miles (17,403 kilometers) away in Port Elizabeth, South Africa.
• Although classified by the FAA as "private use", Amook Bay has scheduled passenger service to Kodiak, Alaska, which is subsidized by the United States Department of Transportation via the Essential Air Service program.
• Amook Bay Seaplane Base (AOS) currently has only 1 runway.
• Amook Bay Seaplane Base has one seaplane landing area designated N/S with a water surface measuring 8,000 by 700 feet.
• Amook Bay Seaplane Base is a privately owned seaplane base located in Amook Bay, a community in the Kodiak Island Borough of the U.S.
• Because of Amook Bay Seaplane Base's relatively low elevation of 0 feet, planes can take off or land at Amook Bay Seaplane Base at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
• In addition to being known as "Amook Bay Seaplane Base", another name for AOS is "AK81".
• The closest airport to Amook Bay Seaplane Base (AOS) is Zachar Bay Seaplane Base (KZB), which is located only 6 miles (10 kilometers) NNE of AOS.