Nonstop flight route between Destin, Florida, United States and Owensboro, Kentucky, United States:
Departure Airport:

Arrival Airport:

Distance from DSI to OWB:
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- About this route
- DSI Airport Information
- OWB Airport Information
- Facts about DSI
- Facts about OWB
- Map of Nearest Airports to DSI
- List of Nearest Airports to DSI
- Map of Furthest Airports from DSI
- List of Furthest Airports from DSI
- Map of Nearest Airports to OWB
- List of Nearest Airports to OWB
- Map of Furthest Airports from OWB
- List of Furthest Airports from OWB
About this route:
A direct, nonstop flight between Destin–Fort Walton Beach Airport (DSI), Destin, Florida, United States and Owensboro-Daviess County Airport (OWB), Owensboro, Kentucky, United States would travel a Great Circle distance of 509 miles (or 819 kilometers).
A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the relatively short distance between Destin–Fort Walton Beach Airport and Owensboro-Daviess County Airport, the route shown on this map most likely still appears to be a straight line.
Departure Airport Information:
IATA / ICAO Codes: | DSI / KDTS |
Airport Names: |
|
Location: | Destin, Florida, United States |
GPS Coordinates: | 30°23'59"N by 86°28'17"W |
Area Served: | Destin, Florida |
Operator/Owner: | Okaloosa County |
Airport Type: | Public |
Elevation: | 22 feet (7 meters) |
# of Runways: | 1 |
View all routes: | Routes from DSI |
More Information: | DSI Maps & Info |
Arrival Airport Information:
IATA / ICAO Codes: | OWB / KOWB |
Airport Name: | Owensboro-Daviess County Airport |
Location: | Owensboro, Kentucky, United States |
GPS Coordinates: | 37°44'20"N by 87°10'0"W |
Area Served: | Owensboro, Kentucky |
Operator/Owner: | Owensboro City & Daviess County |
Airport Type: | Public |
Elevation: | 407 feet (124 meters) |
# of Runways: | 2 |
View all routes: | Routes from OWB |
More Information: | OWB Maps & Info |
Facts about Destin–Fort Walton Beach Airport (DSI):
- Destin–Fort Walton Beach Airport covers an area of 395 acres at an elevation of 22 feet above mean sea level.
- The furthest airport from Destin–Fort Walton Beach Airport (DSI) is Shark Bay Airport (MJK), which is located 11,178 miles (17,990 kilometers) away in Monkey Mia, Western Australia, Australia.
- Because of Destin–Fort Walton Beach Airport's relatively low elevation of 22 feet, planes can take off or land at Destin–Fort Walton Beach Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
- In addition to being known as "Destin–Fort Walton Beach Airport", other names for DSI include "Coleman Kelly Field" and "DTS".
- Destin–Fort Walton Beach Airport (DSI) currently has only 1 runway.
- The closest airport to Destin–Fort Walton Beach Airport (DSI) is Northwest Florida Regional Airport (VPS), which is located only 7 miles (11 kilometers) NNW of DSI.
Facts about Owensboro-Daviess County Airport (OWB):
- Owensboro-Daviess County Airport (OWB) has 2 runways.
- The furthest airport from Owensboro-Daviess County Airport (OWB) is Margaret River Airport (MGV), which is located 11,165 miles (17,969 kilometers) away in Margaret River, Western Australia, Australia.
- Owensboro-Daviess County Airport is a public use airport located three nautical miles southwest of the central business district of Owensboro, a city in Daviess County, Kentucky, United States.
- The closest airport to Owensboro-Daviess County Airport (OWB) is Evansville Regional Airport (EVV), which is located 29 miles (46 kilometers) NW of OWB.
- Owensboro-Daviess County Airport covers an area of 826 acres at an elevation of 407 feet above mean sea level.
- Because of Owensboro-Daviess County Airport's relatively low elevation of 407 feet, planes can take off or land at Owensboro-Daviess County Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
- As per the Federal Aviation Administration, this airport had 16,193 passenger boardings in calendar year 2010, 17,296 in 2011, and 30,795 in 2012.