Nonstop flight route between Muzzafarpur, India and Excursion Inlet, Alaska, United States:

About this route:

A direct, nonstop flight between Muzaffarpur Airport (MZU), Muzzafarpur, India and Excursion Inlet Seaplane Base (EXI), Excursion Inlet, Alaska, United States would travel a Great Circle distance of 6,144 miles (or 9,887 kilometers).

A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the large distance between Muzaffarpur Airport and Excursion Inlet Seaplane Base, the route shown on this map most likely appears curved because of this reason.

Try it at home! Get a globe and tightly lay a string between Muzaffarpur Airport and Excursion Inlet Seaplane Base. You'll see that it will travel the same route of the red line on this map!

Departure Airport Information:

Arrival Airport Information:

Facts about Muzaffarpur Airport (MZU):

• The furthest airport from Muzaffarpur Airport (MZU) is Mataveri International Airport (IPC), which is located 11,524 miles (18,547 kilometers) away in Easter Island, Chile.
• Muzaffarpur Airport (MZU) currently has only 1 runway.
• In addition to being known as "Muzaffarpur Airport", another name for MZU is "मुजफ्फरपुर हवाई अड्डे".
• The closest airport to Muzaffarpur Airport (MZU) is Jai Prakash Narayan International Airport Patna Airport (PAT), which is located 39 miles (63 kilometers) SSW of MZU.
• Because of Muzaffarpur Airport's relatively low elevation of 174 feet, planes can take off or land at Muzaffarpur Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.

Facts about Excursion Inlet Seaplane Base (EXI):

• The closest airport to Excursion Inlet Seaplane Base (EXI) is Gustavus Airport (GST), which is located only 9 miles (15 kilometers) W of EXI.
• Excursion Inlet Seaplane Base is a state owned, public use seaplane base located in Excursion Inlet, in the Haines Borough of the U.S.
• The furthest airport from Excursion Inlet Seaplane Base (EXI) is Port Elizabeth International Airport (PLZ), which is located 10,536 miles (16,956 kilometers) away in Port Elizabeth, South Africa.
• Because of Excursion Inlet Seaplane Base's relatively low elevation of 0 feet, planes can take off or land at Excursion Inlet Seaplane Base at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
• Excursion Inlet Seaplane Base (EXI) currently has only 1 runway.