Nonstop flight route between Utopia Creek, Alaska, United States and Jacksonville, Florida, United States:
Departure Airport:

Arrival Airport:

Distance from UTO to CRG:
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- About this route
- UTO Airport Information
- CRG Airport Information
- Facts about UTO
- Facts about CRG
- Map of Nearest Airports to UTO
- List of Nearest Airports to UTO
- Map of Furthest Airports from UTO
- List of Furthest Airports from UTO
- Map of Nearest Airports to CRG
- List of Nearest Airports to CRG
- Map of Furthest Airports from CRG
- List of Furthest Airports from CRG
About this route:
A direct, nonstop flight between Indian Mountain LRRS Airport (UTO), Utopia Creek, Alaska, United States and Jacksonville Executive at Craig Airport (CRG), Jacksonville, Florida, United States would travel a Great Circle distance of 3,823 miles (or 6,153 kilometers).
A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the large distance between Indian Mountain LRRS Airport and Jacksonville Executive at Craig Airport, the route shown on this map most likely appears curved because of this reason.
Try it at home! Get a globe and tightly lay a string between Indian Mountain LRRS Airport and Jacksonville Executive at Craig Airport. You'll see that it will travel the same route of the red line on this map!
Departure Airport Information:
IATA / ICAO Codes: | UTO / PAIM |
Airport Name: | Indian Mountain LRRS Airport |
Location: | Utopia Creek, Alaska, United States |
GPS Coordinates: | 65°59'34"N by 153°42'14"W |
Operator/Owner: | U.S. Air Force |
Airport Type: | Military |
Elevation: | 1273 feet (388 meters) |
# of Runways: | 1 |
View all routes: | Routes from UTO |
More Information: | UTO Maps & Info |
Arrival Airport Information:
IATA / ICAO Codes: | CRG / KCRG |
Airport Name: | Jacksonville Executive at Craig Airport |
Location: | Jacksonville, Florida, United States |
GPS Coordinates: | 30°20'11"N by 81°30'51"W |
Area Served: | Jacksonville, Florida |
Operator/Owner: | Jacksonville Aviation Authority |
Airport Type: | Public |
Elevation: | 41 feet (12 meters) |
# of Runways: | 2 |
View all routes: | Routes from CRG |
More Information: | CRG Maps & Info |
Facts about Indian Mountain LRRS Airport (UTO):
- Indian Mountain LRRS Airport (UTO) currently has only 1 runway.
- Indian Mountain LRRS Airport is a military airstrip located south of Utopia Creek, in the Yukon–Koyukuk Census Area of the U.S.
- The closest airport to Indian Mountain LRRS Airport (UTO) is Hughes Airport (HUS), which is located only 16 miles (26 kilometers) WNW of UTO.
- Indian Mountain Airport is a United States Air Force military airstrip.
- The furthest airport from Indian Mountain LRRS Airport (UTO) is Port Elizabeth International Airport (PLZ), which is located 10,225 miles (16,456 kilometers) away in Port Elizabeth, South Africa.
Facts about Jacksonville Executive at Craig Airport (CRG):
- Jacksonville Executive at Craig Airport (CRG) has 2 runways.
- The furthest airport from Jacksonville Executive at Craig Airport (CRG) is Shark Bay Airport (MJK), which is located 11,468 miles (18,456 kilometers) away in Monkey Mia, Western Australia, Australia.
- The United States Navy's Blue Angels performed their first airshow at Jacksonville Executive at Craig Airport on June 15, 1946.
- The closest airport to Jacksonville Executive at Craig Airport (CRG) is Naval Station Mayport (NRB), which is located only 7 miles (11 kilometers) NE of CRG.
- Because of Jacksonville Executive at Craig Airport's relatively low elevation of 41 feet, planes can take off or land at Jacksonville Executive at Craig Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.