Nonstop flight route between Amook Bay, Alaska, United States and Poughkeepsie, New York, United States:

About this route:

A direct, nonstop flight between Amook Bay Seaplane Base (AOS), Amook Bay, Alaska, United States and Dutchess County Airport (POU), Poughkeepsie, New York, United States would travel a Great Circle distance of 3,519 miles (or 5,663 kilometers).

A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the large distance between Amook Bay Seaplane Base and Dutchess County Airport, the route shown on this map most likely appears curved because of this reason.

Try it at home! Get a globe and tightly lay a string between Amook Bay Seaplane Base and Dutchess County Airport. You'll see that it will travel the same route of the red line on this map!

Departure Airport Information:

Arrival Airport Information:

Facts about Amook Bay Seaplane Base (AOS):

• Amook Bay Seaplane Base (AOS) currently has only 1 runway.
• The furthest airport from Amook Bay Seaplane Base (AOS) is Port Elizabeth International Airport (PLZ), which is located 10,814 miles (17,403 kilometers) away in Port Elizabeth, South Africa.
• Because of Amook Bay Seaplane Base's relatively low elevation of 0 feet, planes can take off or land at Amook Bay Seaplane Base at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
• In addition to being known as "Amook Bay Seaplane Base", another name for AOS is "AK81".
• The closest airport to Amook Bay Seaplane Base (AOS) is Zachar Bay Seaplane Base (KZB), which is located only 6 miles (10 kilometers) NNE of AOS.

Facts about Dutchess County Airport (POU):

• Dutchess County Airport (POU) has 3 runways.
• Because of Dutchess County Airport's relatively low elevation of 165 feet, planes can take off or land at Dutchess County Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
• Dutchess County Airport is a county-owned public-use airport located on State Route 376 in the Town of Wappinger, Dutchess County, New York, United States, four miles south of the central business district of Poughkeepsie.
• Dutchess County Airport covers an area of 640 acres which contains three runways, two of which are paved.
• The closest airport to Dutchess County Airport (POU) is Stewart International Airport (SWF), which is located only 14 miles (23 kilometers) SW of POU.
• In the 1960s–1980s, the airport had commuter airline service by Command Airways, Colgan Airways,Air North, and others.
• The furthest airport from Dutchess County Airport (POU) is Margaret River Airport (MGV), which is located 11,714 miles (18,852 kilometers) away in Margaret River, Western Australia, Australia.