Nonstop flight route between Amook Bay, Alaska, United States and Varadero, Matanzas Province, Cuba:
Departure Airport:
Arrival Airport:
Distance from AOS to VRA:
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- About this route
- AOS Airport Information
- VRA Airport Information
- Facts about AOS
- Facts about VRA
- Map of Nearest Airports to AOS
- List of Nearest Airports to AOS
- Map of Furthest Airports from AOS
- List of Furthest Airports from AOS
- Map of Nearest Airports to VRA
- List of Nearest Airports to VRA
- Map of Furthest Airports from VRA
- List of Furthest Airports from VRA
About this route:
A direct, nonstop flight between Amook Bay Seaplane Base (AOS), Amook Bay, Alaska, United States and Juan Gualberto Gómez Airport (VRA), Varadero, Matanzas Province, Cuba would travel a Great Circle distance of 4,238 miles (or 6,820 kilometers).
A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the large distance between Amook Bay Seaplane Base and Juan Gualberto Gómez Airport, the route shown on this map most likely appears curved because of this reason.
Try it at home! Get a globe and tightly lay a string between Amook Bay Seaplane Base and Juan Gualberto Gómez Airport. You'll see that it will travel the same route of the red line on this map!
Departure Airport Information:
IATA / ICAO Codes: | AOS / |
Airport Names: |
|
Location: | Amook Bay, Alaska, United States |
GPS Coordinates: | 57°28'17"N by 153°48'55"W |
Area Served: | Amook Bay, Alaska |
Operator/Owner: | Mike Munsey |
Airport Type: | Private |
Elevation: | 0 feet (0 meters) |
# of Runways: | 1 |
View all routes: | Routes from AOS |
More Information: | AOS Maps & Info |
Arrival Airport Information:
IATA / ICAO Codes: | VRA / MUVR |
Airport Names: |
|
Location: | Varadero, Matanzas Province, Cuba |
GPS Coordinates: | 23°2'3"N by 81°26'7"W |
Operator/Owner: | ECASA S.A. |
Airport Type: | Public |
Elevation: | 210 feet (64 meters) |
# of Runways: | 1 |
View all routes: | Routes from VRA |
More Information: | VRA Maps & Info |
Facts about Amook Bay Seaplane Base (AOS):
- The closest airport to Amook Bay Seaplane Base (AOS) is Zachar Bay Seaplane Base (KZB), which is located only 6 miles (10 kilometers) NNE of AOS.
- Amook Bay Seaplane Base has one seaplane landing area designated N/S with a water surface measuring 8,000 by 700 feet.
- Because of Amook Bay Seaplane Base's relatively low elevation of 0 feet, planes can take off or land at Amook Bay Seaplane Base at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
- The furthest airport from Amook Bay Seaplane Base (AOS) is Port Elizabeth International Airport (PLZ), which is located 10,814 miles (17,403 kilometers) away in Port Elizabeth, South Africa.
- In addition to being known as "Amook Bay Seaplane Base", another name for AOS is "AK81".
- Amook Bay Seaplane Base (AOS) currently has only 1 runway.
Facts about Juan Gualberto Gómez Airport (VRA):
- The closest airport to Juan Gualberto Gómez Airport (VRA) is Kawama Airport (VRO), which is located only 10 miles (17 kilometers) NE of VRA.
- There has been 5 significant incidents involving aircraft from or en route to the airport since the 1950s.
- The furthest airport from Juan Gualberto Gómez Airport (VRA) is Cocos (Keeling) Island Airport (CCK), which is located 11,679 miles (18,795 kilometers) away in Cocos Islands, Australia.
- Juan Gualberto Gómez Airport (VRA) currently has only 1 runway.
- In addition to being known as "Juan Gualberto Gómez Airport", another name for VRA is "Aeropuerto Juan Gualberto Gómez".
- Because of Juan Gualberto Gómez Airport's relatively low elevation of 210 feet, planes can take off or land at Juan Gualberto Gómez Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.