Nonstop flight route between Coimbatore, India and Amook Bay, Alaska, United States:

About this route:

A direct, nonstop flight between Coimbatore International Airport (CJB), Coimbatore, India and Amook Bay Seaplane Base (AOS), Amook Bay, Alaska, United States would travel a Great Circle distance of 6,902 miles (or 11,108 kilometers).

A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the large distance between Coimbatore International Airport and Amook Bay Seaplane Base, the route shown on this map most likely appears curved because of this reason.

Try it at home! Get a globe and tightly lay a string between Coimbatore International Airport and Amook Bay Seaplane Base. You'll see that it will travel the same route of the red line on this map!

Departure Airport Information:

Arrival Airport Information:

Facts about Coimbatore International Airport (CJB):

• Coimbatore International Airport (CJB) currently has only 1 runway.
• The furthest airport from Coimbatore International Airport (CJB) is Seymour Airport (GPS), which is located 11,300 miles (18,185 kilometers) away in Baltra Island, Galápagos Islands, Ecuador.
• The airport has one runway that is 9,760 feet in length extended from 8,500 ft to accommodate larger aircraft.
• Car parking at the airport
• Exterior of the airport
• The closest airport to Coimbatore International Airport (CJB) is Calicut International Airport (CCJ), which is located 74 miles (119 kilometers) W of CJB.

Facts about Amook Bay Seaplane Base (AOS):

• Although classified by the FAA as "private use", Amook Bay has scheduled passenger service to Kodiak, Alaska, which is subsidized by the United States Department of Transportation via the Essential Air Service program.
• The furthest airport from Amook Bay Seaplane Base (AOS) is Port Elizabeth International Airport (PLZ), which is located 10,814 miles (17,403 kilometers) away in Port Elizabeth, South Africa.
• In addition to being known as "Amook Bay Seaplane Base", another name for AOS is "AK81".
• The closest airport to Amook Bay Seaplane Base (AOS) is Zachar Bay Seaplane Base (KZB), which is located only 6 miles (10 kilometers) NNE of AOS.
• Because of Amook Bay Seaplane Base's relatively low elevation of 0 feet, planes can take off or land at Amook Bay Seaplane Base at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
• Amook Bay Seaplane Base (AOS) currently has only 1 runway.