Nonstop flight route between Clinton, North Carolina, United States and Vero Beach, Florida, United States:
Departure Airport:

Arrival Airport:

Distance from CTZ to VRB:
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- About this route
- CTZ Airport Information
- VRB Airport Information
- Facts about CTZ
- Facts about VRB
- Map of Nearest Airports to CTZ
- List of Nearest Airports to CTZ
- Map of Furthest Airports from CTZ
- List of Furthest Airports from CTZ
- Map of Nearest Airports to VRB
- List of Nearest Airports to VRB
- Map of Furthest Airports from VRB
- List of Furthest Airports from VRB
About this route:
A direct, nonstop flight between Clinton-Sampson County Airport (CTZ), Clinton, North Carolina, United States and Vero Beach Municipal Airport (VRB), Vero Beach, Florida, United States would travel a Great Circle distance of 520 miles (or 837 kilometers).
A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the relatively short distance between Clinton-Sampson County Airport and Vero Beach Municipal Airport, the route shown on this map most likely still appears to be a straight line.
Departure Airport Information:
IATA / ICAO Codes: | CTZ / KCTZ |
Airport Name: | Clinton-Sampson County Airport |
Location: | Clinton, North Carolina, United States |
GPS Coordinates: | 34°58'30"N by 78°21'56"W |
Area Served: | Clinton, North Carolina |
Operator/Owner: | Sampson County / City of Clinton |
Airport Type: | Public |
Elevation: | 144 feet (44 meters) |
# of Runways: | 1 |
View all routes: | Routes from CTZ |
More Information: | CTZ Maps & Info |
Arrival Airport Information:
IATA / ICAO Codes: | VRB / KVRB |
Airport Name: | Vero Beach Municipal Airport |
Location: | Vero Beach, Florida, United States |
GPS Coordinates: | 27°39'20"N by 80°25'4"W |
Area Served: | Vero Beach, Florida |
Operator/Owner: | City of Vero Beach |
Airport Type: | Public use |
Elevation: | 24 feet (7 meters) |
# of Runways: | 3 |
View all routes: | Routes from VRB |
More Information: | VRB Maps & Info |
Facts about Clinton-Sampson County Airport (CTZ):
- Because of Clinton-Sampson County Airport's relatively low elevation of 144 feet, planes can take off or land at Clinton-Sampson County Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
- The furthest airport from Clinton-Sampson County Airport (CTZ) is Margaret River Airport (MGV), which is located 11,667 miles (18,776 kilometers) away in Margaret River, Western Australia, Australia.
- The closest airport to Clinton-Sampson County Airport (CTZ) is Fayetteville Regional Airport (FAY), which is located 29 miles (47 kilometers) W of CTZ.
- Clinton-Sampson County Airport (CTZ) currently has only 1 runway.
Facts about Vero Beach Municipal Airport (VRB):
- The closest airport to Vero Beach Municipal Airport (VRB) is St. Lucie County International Airport (FPR), which is located only 12 miles (19 kilometers) SSE of VRB.
- Vero Beach Municipal Airport (VRB) has 3 runways.
- Vero Beach Municipal Airport is a public airport 1 mile northwest of Vero Beach in Indian River County, Florida, United States.
- FlightSafety Academy, a leading flight training school and part of FlightSafety International, is also at VRB.
- The furthest airport from Vero Beach Municipal Airport (VRB) is Shark Bay Airport (MJK), which is located 11,565 miles (18,613 kilometers) away in Monkey Mia, Western Australia, Australia.
- Because of Vero Beach Municipal Airport's relatively low elevation of 24 feet, planes can take off or land at Vero Beach Municipal Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.