Nonstop flight route between Smolensk, Russia and Excursion Inlet, Alaska, United States:

About this route:

A direct, nonstop flight between Smolensk South Airport (LNX), Smolensk, Russia and Excursion Inlet Seaplane Base (EXI), Excursion Inlet, Alaska, United States would travel a Great Circle distance of 4,587 miles (or 7,382 kilometers).

A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the large distance between Smolensk South Airport and Excursion Inlet Seaplane Base, the route shown on this map most likely appears curved because of this reason.

Try it at home! Get a globe and tightly lay a string between Smolensk South Airport and Excursion Inlet Seaplane Base. You'll see that it will travel the same route of the red line on this map!

Departure Airport Information:

Arrival Airport Information:

Facts about Smolensk South Airport (LNX):

• Because of Smolensk South Airport's relatively low elevation of 725 feet, planes can take off or land at Smolensk South Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
• The furthest airport from Smolensk South Airport (LNX) is Chatham Islands (CHT), which is located 10,961 miles (17,640 kilometers) away in Waitangi, Chatham Islands, New Zealand.
• Smolensk South Airport (LNX) currently has only 1 runway.
• In addition to being known as "Smolensk South Airport", other names for LNX include "Smolensk-Yuzhniy", "Смоленск-Южный" and "UUBS".
• The closest airport to Smolensk South Airport (LNX) is Mogilev Airport (MVQ), which is located 96 miles (155 kilometers) WSW of LNX.

Facts about Excursion Inlet Seaplane Base (EXI):

• Excursion Inlet Seaplane Base has one seaplane landing area designated NW/SE with a water surface measuring 1,000 by 1,000 feet.
• This airport is included in the National Plan of Integrated Airport Systems for 2011–2015, which categorized it as a general aviation airport.
• Because of Excursion Inlet Seaplane Base's relatively low elevation of 0 feet, planes can take off or land at Excursion Inlet Seaplane Base at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
• The closest airport to Excursion Inlet Seaplane Base (EXI) is Gustavus Airport (GST), which is located only 9 miles (15 kilometers) W of EXI.
• The furthest airport from Excursion Inlet Seaplane Base (EXI) is Port Elizabeth International Airport (PLZ), which is located 10,536 miles (16,956 kilometers) away in Port Elizabeth, South Africa.
• Excursion Inlet Seaplane Base (EXI) currently has only 1 runway.
• Excursion Inlet Seaplane Base is a state owned, public use seaplane base located in Excursion Inlet, in the Haines Borough of the U.S.