Nonstop flight route between Panama City, Florida, United States and Poughkeepsie, New York, United States:
Departure Airport:
Arrival Airport:
Distance from PAM to POU:
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- About this route
- PAM Airport Information
- POU Airport Information
- Facts about PAM
- Facts about POU
- Map of Nearest Airports to PAM
- List of Nearest Airports to PAM
- Map of Furthest Airports from PAM
- List of Furthest Airports from PAM
- Map of Nearest Airports to POU
- List of Nearest Airports to POU
- Map of Furthest Airports from POU
- List of Furthest Airports from POU
About this route:
A direct, nonstop flight between Tyndall Air Force Base (PAM), Panama City, Florida, United States and Dutchess County Airport (POU), Poughkeepsie, New York, United States would travel a Great Circle distance of 1,030 miles (or 1,658 kilometers).
A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the relatively short distance between Tyndall Air Force Base and Dutchess County Airport, the route shown on this map most likely still appears to be a straight line.
Departure Airport Information:
| IATA / ICAO Codes: | PAM / KPAM |
| Airport Name: | Tyndall Air Force Base |
| Location: | Panama City, Florida, United States |
| GPS Coordinates: | 30°4'42"N by 85°34'35"W |
| View all routes: | Routes from PAM |
| More Information: | PAM Maps & Info |
Arrival Airport Information:
| IATA / ICAO Codes: | POU / KPOU |
| Airport Name: | Dutchess County Airport |
| Location: | Poughkeepsie, New York, United States |
| GPS Coordinates: | 41°37'36"N by 73°53'3"W |
| Area Served: | Poughkeepsie, New York |
| Operator/Owner: | Dutchess County |
| Airport Type: | Public |
| Elevation: | 165 feet (50 meters) |
| # of Runways: | 3 |
| View all routes: | Routes from POU |
| More Information: | POU Maps & Info |
Facts about Tyndall Air Force Base (PAM):
- The furthest airport from Tyndall Air Force Base (PAM) is Shark Bay Airport (MJK), which is located 11,235 miles (18,080 kilometers) away in Monkey Mia, Western Australia, Australia.
- Headquarters, First Air Force at Tyndall is part of the Air Combat Command, ensuring the air sovereignty and air defense of the continental United States.
- In the late 1950s into the 1960s, the base transitioned into the F-100 Super Sabre, F-101B, F-102A and TF-102B, F-104 Starfighter, and the F-106A and B aircraft, training interceptor pilots for ADC assignments.
- The closest airport to Tyndall Air Force Base (PAM) is Panama City–Bay County International Airport (PFN), which is located only 11 miles (18 kilometers) NW of PAM.
- Although construction was well underway, the base lacked a name.
- Tyndall Field was opened on 13 January 1941 as a gunnery range.
Facts about Dutchess County Airport (POU):
- The closest airport to Dutchess County Airport (POU) is Stewart International Airport (SWF), which is located only 14 miles (23 kilometers) SW of POU.
- Dutchess County Airport was built by the United States Department of Commerce in the 1930s and was used for pilot training during World War II by the US Army Air Forces.
- The furthest airport from Dutchess County Airport (POU) is Margaret River Airport (MGV), which is located 11,714 miles (18,852 kilometers) away in Margaret River, Western Australia, Australia.
- Dutchess County Airport is a county-owned public-use airport located on State Route 376 in the Town of Wappinger, Dutchess County, New York, United States, four miles south of the central business district of Poughkeepsie.
- In the 1950s, scheduled air carrier service was provided at Dutchess County Airport by Colonial Airlines.
- Dutchess County Airport (POU) has 3 runways.
- Because of Dutchess County Airport's relatively low elevation of 165 feet, planes can take off or land at Dutchess County Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
