Nonstop flight route between Vilanculos, Mozambique and Lake Ozark, Missouri, United States:
Departure Airport:
Arrival Airport:
Distance from VNX to AIZ:
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- About this route
- VNX Airport Information
- AIZ Airport Information
- Facts about VNX
- Facts about AIZ
- Map of Nearest Airports to VNX
- List of Nearest Airports to VNX
- Map of Furthest Airports from VNX
- List of Furthest Airports from VNX
- Map of Nearest Airports to AIZ
- List of Nearest Airports to AIZ
- Map of Furthest Airports from AIZ
- List of Furthest Airports from AIZ
About this route:
A direct, nonstop flight between Vilankulo Airport (VNX), Vilanculos, Mozambique and Lee C. Fine Memorial Airport (AIZ), Lake Ozark, Missouri, United States would travel a Great Circle distance of 9,174 miles (or 14,764 kilometers).
A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the large distance between Vilankulo Airport and Lee C. Fine Memorial Airport, the route shown on this map most likely appears curved because of this reason.
Try it at home! Get a globe and tightly lay a string between Vilankulo Airport and Lee C. Fine Memorial Airport. You'll see that it will travel the same route of the red line on this map!
Departure Airport Information:
| IATA / ICAO Codes: | VNX / FQVL |
| Airport Name: | Vilankulo Airport |
| Location: | Vilanculos, Mozambique |
| GPS Coordinates: | 22°1'6"S by 35°18'47"E |
| Area Served: | Vilankulo |
| Operator/Owner: | Aeroportos de Mocambique (Mozambique Airports Company) |
| Airport Type: | Public |
| Elevation: | 46 feet (14 meters) |
| # of Runways: | 2 |
| View all routes: | Routes from VNX |
| More Information: | VNX Maps & Info |
Arrival Airport Information:
| IATA / ICAO Codes: | AIZ / KAIZ |
| Airport Name: | Lee C. Fine Memorial Airport |
| Location: | Lake Ozark, Missouri, United States |
| GPS Coordinates: | 38°5'45"N by 92°32'58"W |
| Operator/Owner: | City of Osage Beach |
| Airport Type: | Public |
| Elevation: | 869 feet (265 meters) |
| # of Runways: | 1 |
| View all routes: | Routes from AIZ |
| More Information: | AIZ Maps & Info |
Facts about Vilankulo Airport (VNX):
- Vilankulo Airport (VNX) has 2 runways.
- The furthest airport from Vilankulo Airport (VNX) is Hilo International Airport (ITO), which is located 11,749 miles (18,909 kilometers) away in Hilo, Hawaii, United States.
- The closest airport to Vilankulo Airport (VNX) is Benguerra Island Airport (BCW), which is located only 14 miles (22 kilometers) NE of VNX.
- Because of Vilankulo Airport's relatively low elevation of 46 feet, planes can take off or land at Vilankulo Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
Facts about Lee C. Fine Memorial Airport (AIZ):
- Because of Lee C. Fine Memorial Airport's relatively low elevation of 869 feet, planes can take off or land at Lee C. Fine Memorial Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
- The closest airport to Lee C. Fine Memorial Airport (AIZ) is Waynesville-St. Robert Regional Airport (TBN), which is located 33 miles (53 kilometers) SE of AIZ.
- Lee C. Fine Memorial Airport (AIZ) currently has only 1 runway.
- The furthest airport from Lee C. Fine Memorial Airport (AIZ) is Margaret River Airport (MGV), which is located 10,871 miles (17,495 kilometers) away in Margaret River, Western Australia, Australia.
