Nonstop flight route between Watsonville, California, United States and Amook Bay, Alaska, United States:

About this route:

A direct, nonstop flight between Watsonville Municipal Airport (WVI), Watsonville, California, United States and Amook Bay Seaplane Base (AOS), Amook Bay, Alaska, United States would travel a Great Circle distance of 2,033 miles (or 3,271 kilometers).

A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the relatively short distance between Watsonville Municipal Airport and Amook Bay Seaplane Base, the route shown on this map most likely still appears to be a straight line.

Departure Airport Information:

Arrival Airport Information:

Facts about Watsonville Municipal Airport (WVI):

• The airport is uncontrolled, and the CTAF is 122.8 MHz, and the ASOS can be received on 132.275 MHz or by calling 831-724-8794.
• The furthest airport from Watsonville Municipal Airport (WVI) is Tôlanaro Airport (FTU), which is located 11,380 miles (18,315 kilometers) away in Tôlanaro, Madagascar.
• Because of Watsonville Municipal Airport's relatively low elevation of 163 feet, planes can take off or land at Watsonville Municipal Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
• Watsonville Municipal Airport (WVI) has 2 runways.
• The closest airport to Watsonville Municipal Airport (WVI) is Hollister Municipal Airport (HLI), which is located 21 miles (34 kilometers) E of WVI.
• Instrument pilots have been advised that Watsonville is occasionally surrounded by non-IFR traffic that climbs/descends to low stratus layer.

Facts about Amook Bay Seaplane Base (AOS):

• Amook Bay Seaplane Base (AOS) currently has only 1 runway.
• Because of Amook Bay Seaplane Base's relatively low elevation of 0 feet, planes can take off or land at Amook Bay Seaplane Base at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
• The furthest airport from Amook Bay Seaplane Base (AOS) is Port Elizabeth International Airport (PLZ), which is located 10,814 miles (17,403 kilometers) away in Port Elizabeth, South Africa.
• The closest airport to Amook Bay Seaplane Base (AOS) is Zachar Bay Seaplane Base (KZB), which is located only 6 miles (10 kilometers) NNE of AOS.
• In addition to being known as "Amook Bay Seaplane Base", another name for AOS is "AK81".
• Amook Bay Seaplane Base is a privately owned seaplane base located in Amook Bay, a community in the Kodiak Island Borough of the U.S.