Nonstop flight route between Jacksonville, Florida, United States and Cedar City, Utah, United States:
Departure Airport:
Arrival Airport:
Distance from JAX to CDC:
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- About this route
- JAX Airport Information
- CDC Airport Information
- Facts about JAX
- Facts about CDC
- Map of Nearest Airports to JAX
- List of Nearest Airports to JAX
- Map of Furthest Airports from JAX
- List of Furthest Airports from JAX
- Map of Nearest Airports to CDC
- List of Nearest Airports to CDC
- Map of Furthest Airports from CDC
- List of Furthest Airports from CDC
About this route:
A direct, nonstop flight between Jacksonville International Airport (JAX), Jacksonville, Florida, United States and Cedar City Regional Airport (CDC), Cedar City, Utah, United States would travel a Great Circle distance of 1,855 miles (or 2,986 kilometers).
A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the relatively short distance between Jacksonville International Airport and Cedar City Regional Airport, the route shown on this map most likely still appears to be a straight line.
Departure Airport Information:
| IATA / ICAO Codes: | JAX / KJAX |
| Airport Name: | Jacksonville International Airport |
| Location: | Jacksonville, Florida, United States |
| GPS Coordinates: | 30°29'39"N by 81°41'16"W |
| Area Served: | Jacksonville metropolitan area |
| Airport Type: | Public |
| Elevation: | 30 feet (9 meters) |
| # of Runways: | 2 |
| View all routes: | Routes from JAX |
| More Information: | JAX Maps & Info |
Arrival Airport Information:
| IATA / ICAO Codes: | CDC / KCDC |
| Airport Name: | Cedar City Regional Airport |
| Location: | Cedar City, Utah, United States |
| GPS Coordinates: | 37°42'2"N by 113°5'56"W |
| Area Served: | Cedar City, Utah |
| Operator/Owner: | Cedar City Corporation |
| Airport Type: | Public |
| Elevation: | 5622 feet (1,714 meters) |
| # of Runways: | 2 |
| View all routes: | Routes from CDC |
| More Information: | CDC Maps & Info |
Facts about Jacksonville International Airport (JAX):
- Future plans call for expanding the newly built concourses by 2020 and possibly adding a people mover system to the airport, and connecting the airport with the onsite Clarion Hotel via a moving walkway.
- Because of Jacksonville International Airport's relatively low elevation of 30 feet, planes can take off or land at Jacksonville International Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
- Jacksonville International Airport handled 5,605,934 passengers last year.
- On June 7, 1988, an Air National Guard F-16 fighter jet hit 2 wild pigs on the airport's runway while attempting to land.
- The closest airport to Jacksonville International Airport (JAX) is Imeson FieldJacksonville Army AirfieldNaval Auxiliary Air Station Jacksonville #1 (IJX), which is located only 6 miles (9 kilometers) SSE of JAX.
- Jacksonville International Airport (JAX) has 2 runways.
- The airport's two runways form a "V".
- The furthest airport from Jacksonville International Airport (JAX) is Kalbarri Airport (KAX), which is located 11,456 miles (18,436 kilometers) away in Kalbarri, Western Australia, Australia.
Facts about Cedar City Regional Airport (CDC):
- The closest airport to Cedar City Regional Airport (CDC) is Panguitch Municipal Airport (PNU), which is located 40 miles (64 kilometers) ENE of CDC.
- The airport covers 1,040 acres at an elevation of 5,622 feet.
- The furthest airport from Cedar City Regional Airport (CDC) is Sir Gaëtan Duval Airport (RRG), which is located 11,179 miles (17,991 kilometers) away in Rodrigues Island, Mauritius.
- Federal Aviation Administration records say the airport had 7,776 passenger boardings in calendar year 2008, 5,486 in 2009 and 5,997 in 2010.
- Because of Cedar City Regional Airport's high elevation of 5,622 feet, planes must typically fly at a faster airspeed in order to takeoff or land at CDC. Combined with a high temperature, this could make CDC a "Hot & High" airport, where the air density is lower than it would otherwise be at sea level.
- Cedar City Regional Airport (CDC) has 2 runways.
