Nonstop flight route between Oskarshamn, Sweden and Cedar City, Utah, United States:
Departure Airport:

Arrival Airport:

Distance from OSK to CDC:
Share this route:
Jump to:
- About this route
- OSK Airport Information
- CDC Airport Information
- Facts about OSK
- Facts about CDC
- Map of Nearest Airports to OSK
- List of Nearest Airports to OSK
- Map of Furthest Airports from OSK
- List of Furthest Airports from OSK
- Map of Nearest Airports to CDC
- List of Nearest Airports to CDC
- Map of Furthest Airports from CDC
- List of Furthest Airports from CDC
About this route:
A direct, nonstop flight between Oskarshamn Airport (OSK), Oskarshamn, Sweden and Cedar City Regional Airport (CDC), Cedar City, Utah, United States would travel a Great Circle distance of 5,247 miles (or 8,445 kilometers).
A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the large distance between Oskarshamn Airport and Cedar City Regional Airport, the route shown on this map most likely appears curved because of this reason.
Try it at home! Get a globe and tightly lay a string between Oskarshamn Airport and Cedar City Regional Airport. You'll see that it will travel the same route of the red line on this map!
Departure Airport Information:
IATA / ICAO Codes: | OSK / ESMO |
Airport Names: |
|
Location: | Oskarshamn, Sweden |
GPS Coordinates: | 57°21'1"N by 16°29'47"E |
Elevation: | 96 feet (29 meters) |
# of Runways: | 1 |
View all routes: | Routes from OSK |
More Information: | OSK Maps & Info |
Arrival Airport Information:
IATA / ICAO Codes: | CDC / KCDC |
Airport Name: | Cedar City Regional Airport |
Location: | Cedar City, Utah, United States |
GPS Coordinates: | 37°42'2"N by 113°5'56"W |
Area Served: | Cedar City, Utah |
Operator/Owner: | Cedar City Corporation |
Airport Type: | Public |
Elevation: | 5622 feet (1,714 meters) |
# of Runways: | 2 |
View all routes: | Routes from CDC |
More Information: | CDC Maps & Info |
Facts about Oskarshamn Airport (OSK):
- Because of Oskarshamn Airport's relatively low elevation of 96 feet, planes can take off or land at Oskarshamn Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
- The furthest airport from Oskarshamn Airport (OSK) is Chatham Islands (CHT), which is located 11,346 miles (18,260 kilometers) away in Waitangi, Chatham Islands, New Zealand.
- In addition to being known as "Oskarshamn Airport", another name for OSK is "Oskarshamn flygplats".
- The closest airport to Oskarshamn Airport (OSK) is Kalmar Öland Airport (KLR), which is located 47 miles (75 kilometers) S of OSK.
- Oskarshamn Airport (OSK) currently has only 1 runway.
Facts about Cedar City Regional Airport (CDC):
- The furthest airport from Cedar City Regional Airport (CDC) is Sir Gaëtan Duval Airport (RRG), which is located 11,179 miles (17,991 kilometers) away in Rodrigues Island, Mauritius.
- Cedar City Regional Airport (CDC) has 2 runways.
- The airport covers 1,040 acres at an elevation of 5,622 feet.
- The closest airport to Cedar City Regional Airport (CDC) is Panguitch Municipal Airport (PNU), which is located 40 miles (64 kilometers) ENE of CDC.
- Federal Aviation Administration records say the airport had 7,776 passenger boardings in calendar year 2008, 5,486 in 2009 and 5,997 in 2010.
- Because of Cedar City Regional Airport's high elevation of 5,622 feet, planes must typically fly at a faster airspeed in order to takeoff or land at CDC. Combined with a high temperature, this could make CDC a "Hot & High" airport, where the air density is lower than it would otherwise be at sea level.