Nonstop flight route between Luhansk (Lugansk), Ukraine and Excursion Inlet, Alaska, United States:

About this route:

A direct, nonstop flight between Luhansk International Airport (VSG), Luhansk (Lugansk), Ukraine and Excursion Inlet Seaplane Base (EXI), Excursion Inlet, Alaska, United States would travel a Great Circle distance of 5,049 miles (or 8,126 kilometers).

A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the large distance between Luhansk International Airport and Excursion Inlet Seaplane Base, the route shown on this map most likely appears curved because of this reason.

Try it at home! Get a globe and tightly lay a string between Luhansk International Airport and Excursion Inlet Seaplane Base. You'll see that it will travel the same route of the red line on this map!

Departure Airport Information:

Arrival Airport Information:

Facts about Luhansk International Airport (VSG):

• In addition to being known as "Luhansk International Airport", another name for VSG is ""Міжнародний аеропорт Луганськ"".
• Because of Luhansk International Airport's relatively low elevation of 636 feet, planes can take off or land at Luhansk International Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
• The furthest airport from Luhansk International Airport (VSG) is Chatham Islands (CHT), which is located 10,708 miles (17,232 kilometers) away in Waitangi, Chatham Islands, New Zealand.
• The closest airport to Luhansk International Airport (VSG) is Donetsk Sergey Prokofiev International Airport (DOK), which is located 79 miles (128 kilometers) WSW of VSG.
• Luhansk International Airport (VSG) has 2 runways.

Facts about Excursion Inlet Seaplane Base (EXI):

• Excursion Inlet Seaplane Base is a state owned, public use seaplane base located in Excursion Inlet, in the Haines Borough of the U.S.
• Excursion Inlet Seaplane Base (EXI) currently has only 1 runway.
• The furthest airport from Excursion Inlet Seaplane Base (EXI) is Port Elizabeth International Airport (PLZ), which is located 10,536 miles (16,956 kilometers) away in Port Elizabeth, South Africa.
• The closest airport to Excursion Inlet Seaplane Base (EXI) is Gustavus Airport (GST), which is located only 9 miles (15 kilometers) W of EXI.
• Because of Excursion Inlet Seaplane Base's relatively low elevation of 0 feet, planes can take off or land at Excursion Inlet Seaplane Base at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.