Nonstop flight route between Amook Bay, Alaska, United States and Tacloban City, Philippines:

About this route:

A direct, nonstop flight between Amook Bay Seaplane Base (AOS), Amook Bay, Alaska, United States and Daniel Z. Romualdez Airport (TAC), Tacloban City, Philippines would travel a Great Circle distance of 5,238 miles (or 8,429 kilometers).

A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the large distance between Amook Bay Seaplane Base and Daniel Z. Romualdez Airport, the route shown on this map most likely appears curved because of this reason.

Try it at home! Get a globe and tightly lay a string between Amook Bay Seaplane Base and Daniel Z. Romualdez Airport. You'll see that it will travel the same route of the red line on this map!

Departure Airport Information:

Arrival Airport Information:

Facts about Amook Bay Seaplane Base (AOS):

• The closest airport to Amook Bay Seaplane Base (AOS) is Zachar Bay Seaplane Base (KZB), which is located only 6 miles (10 kilometers) NNE of AOS.
• Amook Bay Seaplane Base (AOS) currently has only 1 runway.
• Amook Bay Seaplane Base has one seaplane landing area designated N/S with a water surface measuring 8,000 by 700 feet.
• The furthest airport from Amook Bay Seaplane Base (AOS) is Port Elizabeth International Airport (PLZ), which is located 10,814 miles (17,403 kilometers) away in Port Elizabeth, South Africa.
• In addition to being known as "Amook Bay Seaplane Base", another name for AOS is "AK81".
• Because of Amook Bay Seaplane Base's relatively low elevation of 0 feet, planes can take off or land at Amook Bay Seaplane Base at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.

Facts about Daniel Z. Romualdez Airport (TAC):

• The furthest airport from Daniel Z. Romualdez Airport (TAC) is Orlando Villas-Bôas Regional Airport (MBK), which is nearly antipodal to Daniel Z. Romualdez Airport (meaning Daniel Z. Romualdez Airport is almost on the exact opposite side of the Earth from Orlando Villas-Bôas Regional Airport), and is located 12,364 miles (19,897 kilometers) away in Matupá, Mato Grosso, Brazil.
• Because of Daniel Z. Romualdez Airport's relatively low elevation of 10 feet, planes can take off or land at Daniel Z. Romualdez Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
• In addition to being known as "Daniel Z. Romualdez Airport", another name for TAC is "Paliparang Daniel Z. RomualdezLuparan Daniel Z. Romualdez".
• On November 7–8, 2013, Typhoon Haiyan roared through Tacloban and the Eastern Visayas Region.
• Daniel Z. Romualdez Airport (TAC) currently has only 1 runway.
• The closest airport to Daniel Z. Romualdez Airport (TAC) is Ormoc Airport (OMC), which is located 33 miles (54 kilometers) WSW of TAC.
• Daniel Z. Romualdez Airport handled 1,140,000 passengers last year.
• The administrative building houses the offices of airport staff and the Civil Aviation Authority of the Philippines.
• First known as San Jose Airstrip after the village it is located in, it was constructed as an airstrip for the U.S.
• In Aug 2012, The Department of Transportation and Communications as part of the P319 million modernization of the Tacloban and Dipolog airports allocated P251.6 million for the Tacloban Airport to construct a new apron and taxiway.