Nonstop flight route between Fiumicino (near Rome), Italy and Excursion Inlet, Alaska, United States:

About this route:

A direct, nonstop flight between Fiumicino – Leonardo da Vinci International Airport (FCO), Fiumicino (near Rome), Italy and Excursion Inlet Seaplane Base (EXI), Excursion Inlet, Alaska, United States would travel a Great Circle distance of 5,268 miles (or 8,477 kilometers).

A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the large distance between Fiumicino – Leonardo da Vinci International Airport and Excursion Inlet Seaplane Base, the route shown on this map most likely appears curved because of this reason.

Try it at home! Get a globe and tightly lay a string between Fiumicino – Leonardo da Vinci International Airport and Excursion Inlet Seaplane Base. You'll see that it will travel the same route of the red line on this map!

Departure Airport Information:

Arrival Airport Information:

Facts about Fiumicino – Leonardo da Vinci International Airport (FCO):

• In May 2006, Italy's Civil Aviation Authority announced that it took off the limitation of 3 ramp handlers in Rome Leonardo da Vinci airport.
• Fiumicino – Leonardo da Vinci International Airport (FCO) has 4 runways.
• Leonardo da Vinci is about 35 km by car from Rome's historic city centre.
• In addition to being known as "Fiumicino – Leonardo da Vinci International Airport", another name for FCO is "Fiumicino – Aeroporto Internazionale Leonardo da Vinci".
• In 2000, the new domestic Terminal A opened, and the terminal buildings, then consisting of Terminal A, Terminal AA, Terminal B, and Terminal C, were reorganized.
• The closest airport to Fiumicino – Leonardo da Vinci International Airport (FCO) is Ciampino–G. B. Pastine International Airport (CIA), which is located only 18 miles (30 kilometers) E of FCO.
• Fiumicino – Leonardo da Vinci International Airport handled 36,166,345 passengers last year.
• The furthest airport from Fiumicino – Leonardo da Vinci International Airport (FCO) is Chatham Islands (CHT), which is located 11,975 miles (19,272 kilometers) away in Waitangi, Chatham Islands, New Zealand.
• Security Services transferred from the Polizia di Stato to Aeroporti di Roma in 2000.
• Because of Fiumicino – Leonardo da Vinci International Airport's relatively low elevation of 13 feet, planes can take off or land at Fiumicino – Leonardo da Vinci International Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.

Facts about Excursion Inlet Seaplane Base (EXI):

• The furthest airport from Excursion Inlet Seaplane Base (EXI) is Port Elizabeth International Airport (PLZ), which is located 10,536 miles (16,956 kilometers) away in Port Elizabeth, South Africa.
• Excursion Inlet Seaplane Base (EXI) currently has only 1 runway.
• Excursion Inlet Seaplane Base is a state owned, public use seaplane base located in Excursion Inlet, in the Haines Borough of the U.S.
• Because of Excursion Inlet Seaplane Base's relatively low elevation of 0 feet, planes can take off or land at Excursion Inlet Seaplane Base at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
• The closest airport to Excursion Inlet Seaplane Base (EXI) is Gustavus Airport (GST), which is located only 9 miles (15 kilometers) W of EXI.
• This airport is included in the National Plan of Integrated Airport Systems for 2011–2015, which categorized it as a general aviation airport.