Nonstop flight route between Ladyville (near Belize City), Belize and Jacksonville, Texas, United States:
Departure Airport:
Arrival Airport:
Distance from BZE to JKV:
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- About this route
- BZE Airport Information
- JKV Airport Information
- Facts about BZE
- Facts about JKV
- Map of Nearest Airports to BZE
- List of Nearest Airports to BZE
- Map of Furthest Airports from BZE
- List of Furthest Airports from BZE
- Map of Nearest Airports to JKV
- List of Nearest Airports to JKV
- Map of Furthest Airports from JKV
- List of Furthest Airports from JKV
About this route:
A direct, nonstop flight between Philip S. W. Goldson International Airport (BZE), Ladyville (near Belize City), Belize and Cherokee County Airport (JKV), Jacksonville, Texas, United States would travel a Great Circle distance of 1,080 miles (or 1,738 kilometers).
A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the relatively short distance between Philip S. W. Goldson International Airport and Cherokee County Airport, the route shown on this map most likely still appears to be a straight line.
Departure Airport Information:
| IATA / ICAO Codes: | BZE / MZBZ |
| Airport Name: | Philip S. W. Goldson International Airport |
| Location: | Ladyville (near Belize City), Belize |
| GPS Coordinates: | 17°32'21"N by 88°18'29"W |
| Operator/Owner: | n/a |
| Airport Type: | Public |
| Elevation: | 16 feet (5 meters) |
| # of Runways: | 1 |
| View all routes: | Routes from BZE |
| More Information: | BZE Maps & Info |
Arrival Airport Information:
| IATA / ICAO Codes: | JKV / KJSO |
| Airport Names: |
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| Location: | Jacksonville, Texas, United States |
| GPS Coordinates: | 31°52'9"N by 95°13'3"W |
| Area Served: | Jacksonville, Texas |
| Operator/Owner: | Cherokee County |
| Airport Type: | Public |
| Elevation: | 677 feet (206 meters) |
| # of Runways: | 1 |
| View all routes: | Routes from JKV |
| More Information: | JKV Maps & Info |
Facts about Philip S. W. Goldson International Airport (BZE):
- Philip S. W. Goldson International Airport handled 542,833 passengers last year.
- Philip S. W. Goldson International Airport (BZE) currently has only 1 runway.
- The closest airport to Philip S. W. Goldson International Airport (BZE) is Belize City Municipal Airport (TZA), which is located only 8 miles (13 kilometers) ESE of BZE.
- Because of Philip S. W. Goldson International Airport's relatively low elevation of 16 feet, planes can take off or land at Philip S. W. Goldson International Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
- The furthest airport from Philip S. W. Goldson International Airport (BZE) is Cocos (Keeling) Island Airport (CCK), which is located 11,932 miles (19,203 kilometers) away in Cocos Islands, Australia.
Facts about Cherokee County Airport (JKV):
- Cherokee County Airport (JKV) currently has only 1 runway.
- The furthest airport from Cherokee County Airport (JKV) is Cocos (Keeling) Island Airport (CCK), which is located 10,876 miles (17,503 kilometers) away in Cocos Islands, Australia.
- The closest airport to Cherokee County Airport (JKV) is Tyler Pounds Regional Airport (TYR), which is located 35 miles (57 kilometers) NNW of JKV.
- In addition to being known as "Cherokee County Airport", another name for JKV is "JSO".
- Because of Cherokee County Airport's relatively low elevation of 677 feet, planes can take off or land at Cherokee County Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
- Cherokee County Airport covers an area of 224 acres at an elevation of 677 feet above mean sea level.
