Nonstop flight route between Valladolid, Spain and Lake Ozark, Missouri, United States:
Departure Airport:
Arrival Airport:
Distance from VLL to AIZ:
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- About this route
- VLL Airport Information
- AIZ Airport Information
- Facts about VLL
- Facts about AIZ
- Map of Nearest Airports to VLL
- List of Nearest Airports to VLL
- Map of Furthest Airports from VLL
- List of Furthest Airports from VLL
- Map of Nearest Airports to AIZ
- List of Nearest Airports to AIZ
- Map of Furthest Airports from AIZ
- List of Furthest Airports from AIZ
About this route:
A direct, nonstop flight between Valladolid International Airport (VLL), Valladolid, Spain and Lee C. Fine Memorial Airport (AIZ), Lake Ozark, Missouri, United States would travel a Great Circle distance of 4,441 miles (or 7,147 kilometers).
A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the large distance between Valladolid International Airport and Lee C. Fine Memorial Airport, the route shown on this map most likely appears curved because of this reason.
Try it at home! Get a globe and tightly lay a string between Valladolid International Airport and Lee C. Fine Memorial Airport. You'll see that it will travel the same route of the red line on this map!
Departure Airport Information:
| IATA / ICAO Codes: | VLL / LEVD |
| Airport Names: |
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| Location: | Valladolid, Spain |
| GPS Coordinates: | 41°42'21"N by 4°51'6"W |
| Operator/Owner: | Aeropuertos Españoles y Navegacion Aerea |
| Airport Type: | Public and Military |
| Elevation: | 2775 feet (846 meters) |
| # of Runways: | 2 |
| View all routes: | Routes from VLL |
| More Information: | VLL Maps & Info |
Arrival Airport Information:
| IATA / ICAO Codes: | AIZ / KAIZ |
| Airport Name: | Lee C. Fine Memorial Airport |
| Location: | Lake Ozark, Missouri, United States |
| GPS Coordinates: | 38°5'45"N by 92°32'58"W |
| Operator/Owner: | City of Osage Beach |
| Airport Type: | Public |
| Elevation: | 869 feet (265 meters) |
| # of Runways: | 1 |
| View all routes: | Routes from AIZ |
| More Information: | AIZ Maps & Info |
Facts about Valladolid International Airport (VLL):
- Valladolid International Airport handled 260 passengers last year.
- In addition to being known as "Valladolid International Airport", another name for VLL is "Aeropuerto de Valladolid".
- Valladolid International Airport (VLL) has 2 runways.
- The closest airport to Valladolid International Airport (VLL) is Salamanca-Matacán Airport (SLM), which is located 62 miles (100 kilometers) SSW of VLL.
- The terminal offers all the usual amenities expected by passengers, including a duty-free shop, cafe and restaurant, ATM and information services.
- The furthest airport from Valladolid International Airport (VLL) is Wellington International Airport (WLG), which is nearly antipodal to Valladolid International Airport (meaning Valladolid International Airport is almost on the exact opposite side of the Earth from Wellington International Airport), and is located 12,405 miles (19,964 kilometers) away in Wellington, New Zealand.
Facts about Lee C. Fine Memorial Airport (AIZ):
- The furthest airport from Lee C. Fine Memorial Airport (AIZ) is Margaret River Airport (MGV), which is located 10,871 miles (17,495 kilometers) away in Margaret River, Western Australia, Australia.
- The closest airport to Lee C. Fine Memorial Airport (AIZ) is Waynesville-St. Robert Regional Airport (TBN), which is located 33 miles (53 kilometers) SE of AIZ.
- Because of Lee C. Fine Memorial Airport's relatively low elevation of 869 feet, planes can take off or land at Lee C. Fine Memorial Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
- Lee C. Fine Memorial Airport (AIZ) currently has only 1 runway.
