Nonstop flight route between Amook Bay, Alaska, United States and Goldsboro, North Carolina, United States:

About this route:

A direct, nonstop flight between Amook Bay Seaplane Base (AOS), Amook Bay, Alaska, United States and Seymour Johnson Air Force Base (GSB), Goldsboro, North Carolina, United States would travel a Great Circle distance of 3,696 miles (or 5,949 kilometers).

A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the large distance between Amook Bay Seaplane Base and Seymour Johnson Air Force Base, the route shown on this map most likely appears curved because of this reason.

Try it at home! Get a globe and tightly lay a string between Amook Bay Seaplane Base and Seymour Johnson Air Force Base. You'll see that it will travel the same route of the red line on this map!

Departure Airport Information:

Arrival Airport Information:

Facts about Amook Bay Seaplane Base (AOS):

• Because of Amook Bay Seaplane Base's relatively low elevation of 0 feet, planes can take off or land at Amook Bay Seaplane Base at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
• Amook Bay Seaplane Base has one seaplane landing area designated N/S with a water surface measuring 8,000 by 700 feet.
• The closest airport to Amook Bay Seaplane Base (AOS) is Zachar Bay Seaplane Base (KZB), which is located only 6 miles (10 kilometers) NNE of AOS.
• The furthest airport from Amook Bay Seaplane Base (AOS) is Port Elizabeth International Airport (PLZ), which is located 10,814 miles (17,403 kilometers) away in Port Elizabeth, South Africa.
• Amook Bay Seaplane Base (AOS) currently has only 1 runway.
• In addition to being known as "Amook Bay Seaplane Base", another name for AOS is "AK81".

Facts about Seymour Johnson Air Force Base (GSB):

• The furthest airport from Seymour Johnson Air Force Base (GSB) is Margaret River Airport (MGV), which is located 11,689 miles (18,811 kilometers) away in Margaret River, Western Australia, Australia.
• Seymour Johnson Air Force Base occupies over 3,300 acres in the southeast section of Goldsboro.
• In addition to being known as "Seymour Johnson Air Force Base", another name for GSB is "Seymour Johnson AFB".
• On 8 November 1965, the 335th TFS deployed to Takhli RTAFB, Thailand, for combat operations against North Vietnam.
• The unit initially arrived at Seymour Johnson in October 1985 as a small advance team until October 1986.
• All 4th Fighter Wing F-15Es carry the "SJ" Tailcode.
• In December 1957, the 83d Fighter-Day Wing was inactivated, being replaced at Seymour Johnson by the 4th Fighter-Day Wing and absorbing its assets.
• During the Cuban Missile Crisis, the 4th Tactical Fighter Wing forward deployed its F-105 aircraft to McCoy Air Force Base, Florida, ready to react at a moment's notice for possible combat over Cuba.
• The closest airport to Seymour Johnson Air Force Base (GSB) is Kinston Regional Jetport (ISO), which is located only 20 miles (32 kilometers) E of GSB.