Nonstop flight route between Hoedspruit, South Africa and New York City, New York, United States:

About this route:

A direct, nonstop flight between Air Force Base Hoedspruit (HDS), Hoedspruit, South Africa and John F. Kennedy International Airport (JFK), New York City, New York, United States would travel a Great Circle distance of 8,046 miles (or 12,949 kilometers).

A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the large distance between Air Force Base Hoedspruit and John F. Kennedy International Airport, the route shown on this map most likely appears curved because of this reason.

Try it at home! Get a globe and tightly lay a string between Air Force Base Hoedspruit and John F. Kennedy International Airport. You'll see that it will travel the same route of the red line on this map!

Departure Airport Information:

Arrival Airport Information:

Facts about Air Force Base Hoedspruit (HDS):

• Air Force Base Hoedspruit (HDS) has 2 runways.
• The closest airport to Air Force Base Hoedspruit (HDS) is Hendrik Van Eck Airport (PHW), which is located 30 miles (48 kilometers) NNE of HDS.
• The base was officially opened on 1 July 1978.
• The furthest airport from Air Force Base Hoedspruit (HDS) is Hilo International Airport (ITO), which is located 11,932 miles (19,202 kilometers) away in Hilo, Hawaii, United States.
• South African Express operates daily flights to/from Johannesburg - OR Tambo International Airport and three flights a week to/from Cape Town.
• The base motto is Pro Nostrorum Pace.

Facts about John F. Kennedy International Airport (JFK):

• The furthest airport from John F. Kennedy International Airport (JFK) is Margaret River Airport (MGV), which is located 11,764 miles (18,933 kilometers) away in Margaret River, Western Australia, Australia.
• Because of John F. Kennedy International Airport's relatively low elevation of 13 feet, planes can take off or land at John F. Kennedy International Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
• The Avro Jetliner landed at JFK on April 18, 1950 and maybe in January 1951.
• On March 19, 2007 JFK became the first airport in the United States to receive the Airbus A380 with passengers aboard.
• John F. Kennedy International Airport (JFK) has 4 runways.
• The Port Authority leased the airport property from the City of New York in 1947 and maintains this lease today.
• The closest airport to John F. Kennedy International Airport (JFK) is Flushing Airport (closed 1984) (FLU), which is located only 10 miles (16 kilometers) NNW of JFK.
• The Port of New York Authority originally planned a single 55-gate terminal, but the major airlines did not agree with this plan, arguing that the terminal would be far too small for future traffic.
• Terminal 4 is able to handle the Airbus A380 and was developed by LCOR, Inc and is managed by JFK International Air Terminal LLC, a subsidiary of the Schiphol Group.
• John F. Kennedy International Airport handled 50,423,765 passengers last year.
• JFK opened with six runways and a seventh under construction.
• JFK was designed for aircraft up to 300,000-pound gross weight and had to be modified in the late 1960s to accommodate Boeing 747s.