Nonstop flight route between Valledupar, Colombia and Amook Bay, Alaska, United States:
Departure Airport:
Arrival Airport:
Distance from VUP to AOS:
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- About this route
- VUP Airport Information
- AOS Airport Information
- Facts about VUP
- Facts about AOS
- Map of Nearest Airports to VUP
- List of Nearest Airports to VUP
- Map of Furthest Airports from VUP
- List of Furthest Airports from VUP
- Map of Nearest Airports to AOS
- List of Nearest Airports to AOS
- Map of Furthest Airports from AOS
- List of Furthest Airports from AOS
About this route:
A direct, nonstop flight between Alfonso López Pumarejo Airport (VUP), Valledupar, Colombia and Amook Bay Seaplane Base (AOS), Amook Bay, Alaska, United States would travel a Great Circle distance of 5,261 miles (or 8,467 kilometers).
A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the large distance between Alfonso López Pumarejo Airport and Amook Bay Seaplane Base, the route shown on this map most likely appears curved because of this reason.
Try it at home! Get a globe and tightly lay a string between Alfonso López Pumarejo Airport and Amook Bay Seaplane Base. You'll see that it will travel the same route of the red line on this map!
Departure Airport Information:
IATA / ICAO Codes: | VUP / SKVP |
Airport Names: |
|
Location: | Valledupar, Colombia |
GPS Coordinates: | 10°26'6"N by 73°14'57"W |
Area Served: | Valledupar, Colombia |
Operator/Owner: | Aerocivil Colombia |
Airport Type: | Public |
Elevation: | 456 feet (139 meters) |
# of Runways: | 1 |
View all routes: | Routes from VUP |
More Information: | VUP Maps & Info |
Arrival Airport Information:
IATA / ICAO Codes: | AOS / |
Airport Names: |
|
Location: | Amook Bay, Alaska, United States |
GPS Coordinates: | 57°28'17"N by 153°48'55"W |
Area Served: | Amook Bay, Alaska |
Operator/Owner: | Mike Munsey |
Airport Type: | Private |
Elevation: | 0 feet (0 meters) |
# of Runways: | 1 |
View all routes: | Routes from AOS |
More Information: | AOS Maps & Info |
Facts about Alfonso López Pumarejo Airport (VUP):
- Because of Alfonso López Pumarejo Airport's relatively low elevation of 456 feet, planes can take off or land at Alfonso López Pumarejo Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
- In addition to being known as "Alfonso López Pumarejo Airport", another name for VUP is "Aeropuerto Alfonso López Pumarejo".
- The furthest airport from Alfonso López Pumarejo Airport (VUP) is Christmas Island Airport (XCH), which is nearly antipodal to Alfonso López Pumarejo Airport (meaning Alfonso López Pumarejo Airport is almost on the exact opposite side of the Earth from Christmas Island Airport), and is located 12,365 miles (19,899 kilometers) away in Christmas Island, Australia.
- Alfonso López Pumarejo Airport (VUP) currently has only 1 runway.
- The closest airport to Alfonso López Pumarejo Airport (VUP) is La Mina Airport Jorge Isaacs Airport (MCJ), which is located 75 miles (121 kilometers) NE of VUP.
Facts about Amook Bay Seaplane Base (AOS):
- Amook Bay Seaplane Base (AOS) currently has only 1 runway.
- Amook Bay Seaplane Base is a privately owned seaplane base located in Amook Bay, a community in the Kodiak Island Borough of the U.S.
- Because of Amook Bay Seaplane Base's relatively low elevation of 0 feet, planes can take off or land at Amook Bay Seaplane Base at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
- The closest airport to Amook Bay Seaplane Base (AOS) is Zachar Bay Seaplane Base (KZB), which is located only 6 miles (10 kilometers) NNE of AOS.
- In addition to being known as "Amook Bay Seaplane Base", another name for AOS is "AK81".
- The furthest airport from Amook Bay Seaplane Base (AOS) is Port Elizabeth International Airport (PLZ), which is located 10,814 miles (17,403 kilometers) away in Port Elizabeth, South Africa.