Nonstop flight route between New York City, New York, United States and Goldsboro, North Carolina, United States:

About this route:

A direct, nonstop flight between John F. Kennedy International Airport (JFK), New York City, New York, United States and Seymour Johnson Air Force Base (GSB), Goldsboro, North Carolina, United States would travel a Great Circle distance of 431 miles (or 694 kilometers).

A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the relatively short distance between John F. Kennedy International Airport and Seymour Johnson Air Force Base, the route shown on this map most likely still appears to be a straight line.

Departure Airport Information:

Arrival Airport Information:

Facts about John F. Kennedy International Airport (JFK):

• Terminal 2 opened in 1962 as the home of Northeast Airlines, Braniff and Northwest Airlines, and is now exclusively used and operated by Delta Air Lines.
• John F. Kennedy International Airport handled 50,423,765 passengers last year.
• John F. Kennedy International Airport (JFK) has 4 runways.
• The closest airport to John F. Kennedy International Airport (JFK) is Flushing Airport (closed 1984) (FLU), which is located only 10 miles (16 kilometers) NNW of JFK.
• The Avro Jetliner landed at JFK on April 18, 1950 and maybe in January 1951.
• Because of John F. Kennedy International Airport's relatively low elevation of 13 feet, planes can take off or land at John F. Kennedy International Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
• The furthest airport from John F. Kennedy International Airport (JFK) is Margaret River Airport (MGV), which is located 11,764 miles (18,933 kilometers) away in Margaret River, Western Australia, Australia.
• British Airways is currently evaluating the future of Terminal 7, as its lease with the Port Authority ends in 2015.
• On March 19, 2007 JFK became the first airport in the United States to receive the Airbus A380 with passengers aboard.

Facts about Seymour Johnson Air Force Base (GSB):

• The 335th and 336th Fighter Squadrons are capable of deploying worldwide on short notice and immediately generating combat power., while the 307th, 333rd and 334th Fighter Squadrons are responsible for training all F-15E Strike Eagle aircrews for the U.S.
• The furthest airport from Seymour Johnson Air Force Base (GSB) is Margaret River Airport (MGV), which is located 11,689 miles (18,811 kilometers) away in Margaret River, Western Australia, Australia.
• In addition to being known as "Seymour Johnson Air Force Base", another name for GSB is "Seymour Johnson AFB".
• The 76th Training Wing was activated at Seymour Johnson on 26 February 1943 and the airfield's mission was changed to training replacement pilots for the P-47 Thunderbolt.
• Construction of Seymour Johnson Field started on 9 March 1942 and by 10 July 1942 the 333d Base HQ and Air Base Squadron was established as the host unit.
• In 1974, the wing mission reverted to training, with increased emphasis on short-term European contingency support.
• During the Cuban Missile Crisis, the 4th Tactical Fighter Wing forward deployed its F-105 aircraft to McCoy Air Force Base, Florida, ready to react at a moment's notice for possible combat over Cuba.
• The closest airport to Seymour Johnson Air Force Base (GSB) is Kinston Regional Jetport (ISO), which is located only 20 miles (32 kilometers) E of GSB.
• Interestingly, the namesake of the base, Seymour Johnson, was never part of the Air Force.